Some Brewing Math!

Some examples of some brewing math for practice!



A grist mill has a capacity of 1500 [kg/h]. How much time do you need to crush a grist load of 2500kg?

Since 1500 kg takes 1 hour but you have 2500 kg then:

2500kg/1500 kg/h = 1.6 ( 1.6 x 60 = 96 = 1 hour and 36 minutes)



You have 300 hl of kettle full wort at 10.5% you wish to cast out at 12.5%. How much hot cast wort will you have at 12.5%?

(300*10.5) = ( x = 12.5)

300 * 10.5 / 12.5 = 253hl



With kettle full wort before the boil of 300hl you boiled for 1 hour. After boiling you had 253hl. What is your percentage of hourly evaporation?

300 - 253 = 47

47 * 100 / 300 = 15.6% is your percentage of hourly evaporation.



Math is not my strong point so if you do find any mistakes please let me know... I am using this as practice and have been practicing my brewing math since I got out of school... I'll post some more equations over time.

I also hope that this may help who ever reads this.